Basic Mathematical Operators
The Reasoning section of every competitive exam includes questions from the topic“Mathematical Operators”.
This topic is considered to be quiet important and every year a
2-3 number of questions are asked from this topic. We are providing you
different types of questions were asked which will surely help you in
the upcoming SSC Exams.
This section deals with questions on simple mathematical operations. Here, the four fundamental operations — addition, subtraction, multiplication and division and also statements such as less than\ 'greater than', 'equal to', 'not equal to, etc. are represented by symbols, different from the usual ones. The questions involving these operations are set using artificial symbols.The candidate has to substitute the real signs and solve the questions accordingly, to get the answer.
Example:
(36 -12) ÷4 + 6 + 2 x 3 = 24 ÷ 4 + 6 + 2 x 3 (Solving Bracket)
= 6 + 6 + 2 x 3 (Solving Division)
= 6+6+6 (Solving Multiplication)
= 18 (Solving Addition)
Ex 1: if ‘×’ means ‘-’, ‘÷’ means ‘+’, + means ‘×’, then 18 × 5 ÷ 5 +6 is equal to
(a) 58
(b) 49
(c) 43
(d) 37
Solution: (c)
Change of symbols according to the question,
? = 18 × 5 ÷ 5 +6 = 18 – 5 +5 × 6
= 18 – 5 + 30 = (18 +30) = 43
Ex : If the following equations has to be balance, then the signs of which of the following options will be used?
24 6 12 16 = 0
(a) - , + and +
(b) ÷, + and ÷
(c) -, - and -
(d) ÷, + and –
Solution: (d)
From Option (d)
Hence, option (d) is correct.
Ex: Which one of the given interchange in signs would make the given equation correct?
10 – 2 +9 ×2÷4=19
(a) – and ÷
(b) – and +
(c) ÷ and ×
(d) × and ÷
Solution: (a)
Let us check the options one by one
From option (a),
As options (a) gives us the correct answer. Hence, there in no need to check other options
Ex: If 9 ×5×2 = 529 and 4 ×7×2 =724, then 3×9×8 =?
(a) 983
(b) 839
(c) 938
(d) 893
Solution: (a)
As,
=983
This section deals with questions on simple mathematical operations. Here, the four fundamental operations — addition, subtraction, multiplication and division and also statements such as less than\ 'greater than', 'equal to', 'not equal to, etc. are represented by symbols, different from the usual ones. The questions involving these operations are set using artificial symbols.The candidate has to substitute the real signs and solve the questions accordingly, to get the answer.
Different types of questions covered in this chapter are as follows
- Symbol Substitution
- Balancing the Equation
- Interchange of Signs and Numbers
- Trick Based Mathematical Operations
Example:
(36 -12) ÷4 + 6 + 2 x 3 = 24 ÷ 4 + 6 + 2 x 3 (Solving Bracket)
= 6 + 6 + 2 x 3 (Solving Division)
= 6+6+6 (Solving Multiplication)
= 18 (Solving Addition)
Type 1: Symbol Substitution
In this type of question, a candidate is provided with substitutes for various mathematical symbols, followed by a question involving calculation of an expression or choosing the correct/ incorrect equation. The candidate is required to put in the real signs in the given equation and then solve the questions as required.Ex 1: if ‘×’ means ‘-’, ‘÷’ means ‘+’, + means ‘×’, then 18 × 5 ÷ 5 +6 is equal to
(a) 58
(b) 49
(c) 43
(d) 37
Solution: (c)
Change of symbols according to the question,
? = 18 × 5 ÷ 5 +6 = 18 – 5 +5 × 6
= 18 – 5 + 30 = (18 +30) = 43
Type2: Balancing the Equation
In this type of questions, the signs in one of the alternatives are required to fill up the blank spaces for the signs is order to balance the given equationEx : If the following equations has to be balance, then the signs of which of the following options will be used?
24 6 12 16 = 0
(a) - , + and +
(b) ÷, + and ÷
(c) -, - and -
(d) ÷, + and –
Solution: (d)
From Option (d)
Hence, option (d) is correct.
Type 3: Interchange of Signs and Numbers
In this type of questions, the given equation becomes correct and fully balanced when either two signs of the equation or both the numbers and the signs of the equation are interchanged. The candidate is required to find the correct pair of signs and numbers from the given alternatives.Ex: Which one of the given interchange in signs would make the given equation correct?
10 – 2 +9 ×2÷4=19
(a) – and ÷
(b) – and +
(c) ÷ and ×
(d) × and ÷
Solution: (a)
Let us check the options one by one
From option (a),
As options (a) gives us the correct answer. Hence, there in no need to check other options
Type 4: Trick Based Mathematical Operations
The questions are based on simple mathematical operations that do not come under any of the above given types coverd here. These questions can be based on several different patterns.Ex: If 9 ×5×2 = 529 and 4 ×7×2 =724, then 3×9×8 =?
(a) 983
(b) 839
(c) 938
(d) 893
Solution: (a)
As,
=983
0 comments:
Post a Comment