# Simple Tricks to solve Simple Interest for Competitive exams

## Simple Interest (SI)

If the interest on a sum borrowed for certain period is calculated uniformly, it is called simple interest(SI). (fix percentage of principal)
Principal (sum)
Principal (or the sum) is the money borrowed or lent out for a certain period. It is denoted by P.
What is Amount?
The Addition of Simple Interest and Principle is called the Amount.
A = S.I + P ( Principle )
Interest
Interest is the extra money paid by the borrower to the owner (lender) as a form of compensation for the use of the money borrowed calculated on the basis of Principle.
Time
This is the duration for which money is lend / borrowed.
Rate of Interest
It is the rate at which the interest is charge on principal.
What is Per annul means?
"Rate of interest R%  per annum" means that the interest for one year on a sum. If not stated explicitly, rate of interest is assumed to be for one year.
Formulas Need to Remember
S.I =[( P X R X T )/( 100 )].
Where P = Principle, R = Rate of per annul, T = Number of years
From the above formula , we can derive the followings
P=(100×SI)/ RT
R=(100×SI)/ PT
T=(100×SI)/ PR

Some Tricks to Solve easily
Trick 1:
If a sum of money becomes “n” times in “T years” at simple interest, then the rate of interest per annum can be given be

Trick 2:
If an amount P1 is lent out at simple interest of R1% per annum and another amount P2 at simple interest rate of R2% per annum, then the rate of interest for the whole sum can be given by

Trick 3: A sum of money at simple interest n1 itself in t1 year. It will become n2 times of itself in (If Rate is constant)

Trick 4:
In what time will the simple interest be “n” of the principal at “r %” per annum:-
rt =n x 100
Trick 5:
If a certain sum of money is lent out in n parts in such a manner that equal sum of money is obtained at simple interest on each part where interest rates are R1, R2, ... , Rn respectively and time periods are T1, T2, ... , Tn respectively, then the ratio in which the sum will be divided in n parts can be given by

Ex. 1. Find the simple interest on Rs.400 for 5 years at 6 per cent.
Solution:

Interest for a number of days
When the time is given in days or in years and days, 365 days are reckoned to a year. But when the time is given in months and days, 12 months are reckoned to a year and 30 days to the month. The day on which the money is paid back should be include be but not the day on which it is borrowed, ie, in counting, the first day is omitted.
Ex. 2. Find the simple interest on Rs.306. 25 from March 3rd to July 27th at  per annum.
Solution:
Interest = Rs.
=  = Rs. 4.59
To find principal:-
Since I =
Ex.3. What sum of money will produce Rs.143 interest in   years at  p.c. simple interest?
Solution:
Let the required sum be Rs. P. Then
Rs P =
To find rate %:-
Since I =

Ex. 4. A sum of Rs.468.75 was lent out at simple interest and at the end of 1 year 8 months the total amount was Rs500. Find the rate of interest per cent annum.
Solution:
Here, P =Rs468.75, t =  or
I = Rs.(500-468.75) = Rs.31.25
rate p.c. =
To find Time:-
Since, I = P t r / 100
Ex. 5. In what time will Rs.8500 amount to Rs.15767.50 at  per cent per annum?
Solution:
Here , interest = Rs.15767.50 – Rs.8500 =Rs.7267.50

Miscellaneous Examples on Simple Interest:-
Ex.6: The simple interest on a sum of money is 1/9th of the principal, and the number of years is equal to the rate per cent per annum. Find the rate per cent.
Solution:
Let principal = P, time = t year, rate = t
Then,
Hence, rate =  %
Direct formula:
Rate = time =  %
Ex. 7: The rate of interest for the first 2 yrs is 3% per annum, for the next 3 years is 8% per annum and for the period beyond 5 years 10% per annum.To fetch an interest of 1520 in six years, money did he deposit?
Solution
Let his deposit be = Rs 100
Interest for first 2 yrs = Rs 6
Interest for next 3 yrs = Rs 24
Interest for the last year = Rs 10
Total interest = Rs 40
When interest is Rs 40, deposited amount is Rs 100
when interest is Rs 1520, deposited amount =  = Rs 3800
Direct formula:
Principle = Interest*100/r1t1+r2t2+r3t3 =  =Rs 3800
Ex.8: A sum of money doubles itself in 10 years at simple interest. What is the rate of interest?
Solution:
Let the sum be Rs 100
After 10 years it becomes Rs 200
Interest = 200 - 100 = 100
Then, rate =  =
Direct formula:
Time × Rate = 100 (Multiple number of principal – 1)
Or, Rate =
Using the above formula rate =
Ex.9: A sum was put at a certain rate for 2 yrs. Had it been put at 3% higher rate, it would have fetched Rs 300 more. Find the sum.
Solution:
Let the sum be Rs x and the original rate be y% per annum. Then, new rate = (y+3) % per annum

xy +3x – xy =15,000 or, x =5000
Thus, the sum =Rs 5000